A yeast population grows as shown in the table below. Time is measured in hours. Find the rmax (per hour) and ra (actual r over the entire time period) for this population.

Use K= 320

0 |
10 |

1 |
20 |

2 |
40 |

3 |
75 |

4 |
140 |

5 |
210 |

6 |
273 |

7 |
300 |

8 |
310 |

9 |
315 |

10 |
318 |

11 |
319 |

12 |
317 |

13 |
318 |

14 |
319 |

15 |
315 |

16 |
319 |

Hint: Find the natural log of N and complete column 3. Then find the natural log of (K- N)/N and then complete column 4. Prepare graphs of columns 2, 3, and 4 versus time. For rmax find the slope during the exponential phase of growth (hours 0-4, for example). For ra, find the slope of the values computed in column 4 versus time.

Was this article helpful?

## Post a comment